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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Try substituting cot(theta)=a(n); so you have a(n+1)=(cos(theta)+1)/sin(theta) which is cot(theta/2). As limit tends to infinity if a_1=cot(theta), a_n tends to cot(theta/2^(n-1))
how did u think of this particular substitution
I have done this same question before lmao
'Twas in some pirated allen sheet.
But anyways, 1+a_n² gives you an idea that its either tan or cot
(We usually go for trignometric substitutions when algebraic approach is not bery useful)
alr ill try using that
+solved @SirLancelotDuLac
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