quadratic
how can p be a prime number
Because I can write ax2 + bc + c - p as a(x-A)(x-B) , where a and b are the roots, and that expression will equal to p, which is a prime number, but it also has 3 factors according to LHS?
Because I can write ax2 + bc + c - p as a(x-A)(x-B) , where a and b are the roots, and that expression will equal to p, which is a prime number, but it also has 3 factors according to LHS?
