quadratic
how can p be a prime number
Because I can write ax2 + bc + c - p as a(x-A)(x-B) , where a and b are the roots, and that expression will equal to p, which is a prime number, but it also has 3 factors according to LHS?
13 Replies
@Apu
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Thats the solutions bro
The ans is zero cause p cant hve 3 factors
oh
thats it?
🔥
Yeah
Maybe I should refine it a little bit
Ans is indeed 0
P can't have 3 factors but the given equation can be true
ax^2+bx+c=p this one na?
Haan
Ha that can be true but niche wala to ni ho payega
Not necessary that ax^2+bx+c has 2 real roots though.
Furthermore, its possible one or more of the factors turn out to be 1.
Maximum two roots I guess
Exactly what I'm saying
ou