23 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Please share an attempt
during ascend i assumed initial velocity = u, and at the top final vel = 0, then for decent initial vel = 0 and i assumed final vel = v, used v²=u²+2as equation for both, now we don't know what v and u are (for ascent/descent), which i found using work energy theorem for both ascent and descent separately
WE theorem did not follow where it is being used
do you have an fbd?
acceleration will be different mainly, going up and going down
yes
let me make again
im sending
while going up grav and friction are in the same direction
while going down, grav and friction are opposite.
distance is the same
3 eqns, 3 variables :) solve (a up, a down, mu)
that's the thing, in solution during ascent friction is acting upwards and mgsinθ downwards
idk why
why is friction up
lol how bro.
anyway its not up or down, but along the direction of the plane
not the first time this happened, i think jee mains questions are uk...
ie gsintheta
not properly made
and due to normal force =mu gcostheta
gsinθ is alright
so they will be additive na
cos both are down the plane
whaqt is the answer?
if it is 3 then what we are discussing works
friction should be down the plane bcuz friction prevents relative motion, but in solution it's given its acting up the plane thats the issue
yes
3
then solution is made by a noob
how did he get 3 :S
no clue lol
lets simplify this,
direc of acceleration is same while going up (ie downwards)
while going down, this acceleration magnitude is smaller since friction is upwards
that is all ;D
alright I'll give it another try and see
and since s = 1/2 at2
you are sorted
a up = 4 a down
rest is trig tan theta value etc
i know this is a really badly written solution :P but hope you followed the logic
ohkk i get it now
yes that's correct
thanks
+solved @iTeachChem
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