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@Gyro Gearloose
Note for OP
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The electric field in such a case is given by grad.V
-dv/dx = e right?
Engineering LibreTexts
5.14: Electric Field as the Gradient of Potential
We defined the scalar electric potential field V(r) as the electric potential difference at r relative to a datum at infinity. In this section, we address the “inverse problem” –…
-(dV/dx i cap+ dV/dy j cap + dV/dz k cap) to be precise (partial derivatives)
but i didn't understood what it is trying to say
like what it means
that is my doubt here
Basically apko jo potential hai region me wha pr jo Electric field aayegi E=dv/dx thru partial derivative usme apko ek particular point par ek 1uC k charge p force nikalna hai
jo ki F=qE se ayega
Ap partial derivative logi to Electric field x y z ke terms me aayegi
Us x y z ki jagh apko wo point jo dia hai uske coordinate rakhna hai
Ah sorry. Are you clear with partial derivatives?
yeah i am okay with that part
ok let me try
yeah sure