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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.This seems simple let x=t³ theb dx=3t²dt and this is e^t(3t²)
Which is again standard.
ughh consectuive byparts
Just do it like e^t(f-f'+f"-f'"....
yepp
(Like its a good thing to remember)
its 6 right
f(x) = 3t^2-6t+6
how do u get the limit tho
yep
i applied lhopital and got 2(x^-2/3 -x^-1/3)
x tending 0
6t-3t^2 /t
are just cancel t out
limit ka t and hamara t alag hai
put t^3 as x
hn
wdym
ye kya h
aa gya
thanx ppl
Its just like
A way to remember how to do
baar baar byparts lagake general result
ahh
@SirLancelotDuLac yeh itne aasan aasan ques bhi nhi hue 😭
am just not able to give my 100% in exam
like jitna dimaag hai uss hisaab se kam marks aa rhe
repeatedly
+solved @SirLancelotDuLac @Imine
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