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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.which book is this from?
module
oh okk okk
Huhhhhh
Was too much work lmao
One hell of a question
@hardcoreisdead bro wake up
awake man
Yeah I know it was like
"Wake up bro, I cooked 🗣️"
lolol
The question's language is very misleading though
Unless you assume A could be two things
There's no way you could reach this
And the question says A compound A
Which conditions you to think of A as one single entity
yaar i was taught "oily" liquid is N-nitroso compound
Almost all amines are oily
Not all
which are generally produced when 2 deg amines react with hno2
I've seen aniline in the lab boi
It is oily
That info just confuses more than it helps though
So I get you on this one
Do the answers match though?
I hope I haven't missed a carbon this time
@hardcoreisdead
Ho gaya?
bruh the "rearrangement" here means beckmann?
bs ques
wc chala gya tha lol
Yeah.....
Lmao koi ni
What else could it mean if it's an oxime....
true true
still
Have you studied any other rearrangements of oximes 😭
i couldve tautomerised it and called rearrangement
I mean par double bond kahan hai uske liye
Nitroso bana doge acchan
Got you
But that's not rearrangement
That's equilibrium between the two
the blue circle aint possible anyways cause c6 ha
Rearrangement is when the product is entirely something new
Ohh
I didn't see
Isiliye confused tha mai lmao
Ki inme kaise differentiate karun ab
achaa
You get the idea though right?
Answer maybe thoda idhar udhar hoga 'cause I didn't see ki 6 carbons mentioned hain
That's why I differentiated using that word rapidly
Kyunki ek aromatic and ek aliphatic
There would be a difference in their rates
ok i got the part where F is aniline is oily
Yup
how do u get D from F
F tells you 6 carbons hain
Vaisa vala beckmann product kya hoga
D
This is wild reverse engineering I know but dekh ke idea lagna chahiye
ig we have to back track
whi
Yeah
Like dekho
1 tip
Sabse pehle du
And whenever you see DU being equal to or more than 4
There is a very high chance ki benzene ring hai
true
So it's safe to assume for a trial run
Nahi chala to kuch or socho
Btw you took away that azide vala doubt?
alcohol dont react with nh4oh right?
ho gya tha
They'd deprotonate
Nothing else I suppose
ok so that tells us A cant be an alcohol with a double bond somewhere
it must have some c=o
And actually alcohol nahi hai that's very apparent from the fact ki aage kya hone vala hai
yepp
Aage beckmann and stuff won't proceed with alcohol vagahra too
yaar possible A nikalna is hard
Thoda sochne se aayega
since benzaldehyde + a methyl somehwere is also possible
That'd not be given the conditions I suppose
Kyunki ya hi jayega
can react with nh4oh to oxime and then give beckmann
best option is to find D
going by the options we see that given compound D (option C) might be correct
oh ka nucleophilic attack
and then kicks out Ph-NH(-)
See I thought about it just now that you mentioned
That CH3 on a benzaldehyde thing
but then Ph-Nh(-) K(+) aayea
That could work as well
But options me bas Ph
Hai
Not a CH3 anywhere on the Ph
That prompts you to not think of that
tbf options should go like "compound B MIGHT be .."
Yeah
without options this is lowkey impossible
So ofc there is a might be here
You don't even know what you're starting with
Not even lowkey
It is
It is impossible without the options
truee
It's matching up Right?
No issues now?
drawing it out
Hmm kar lo
By far the most advanced type ka question
That you've shared
Aise bohot aate hain
I kinda hate them but har year aate hain aise vaale
this is given in "mains" section lol
not really
generally they have reasons to back their answers up
Do pyqs boi:)
Post Covid, they've ruined that thing only
Aakash is weird
Only possible arrangement
What is this G rxn tho
Ohh
G is just methylamine
and saath mein benzoic acid banega
@Enamine close??
I feel like white powder bola hai
Carboxylic acids are usually white powders
Benzoic acid ke to white crystals aate hain
methylamine is gas 💀
mb
Tumhara B and C to same hi hai
Koi na 🙂
nuh uh
look at the grp anti to -oh of N
jo anti hota whi migrate karta
Accha ohh that way
Alright I see
Hmm hmm
Now I get it
A ek hi tha
acetophenone
Yup
It got clear with that C6 vaali chiz
yepp
Good kossan
we determined F was aniline cuz DU=4 and oily right??
$$\textbf{maja aaya}$$
Enamine
lolol
i have much much better ques
(in doubts)
lol
Yeah yeah that
Oily vala isn't a necessary detail kyunki kitne hi yaad rakhoge
Bhai mujhe accha laga yaar 😭
Maine ye thodi kaha isse mushkil poocha nahi tumne koi
true
haan acha toh tha
Amines 4 vaale me thoda issue aa raha hai
I feel like decarboxylation hona chahiye tha heating pe
But ab nahi lag raha
Us thread pe aajayo
some ppl said whi hoga
i didnt understand why
Beta carbon ke N hai
That too in the same plane
As COOH
sir are you good with maths as well? @Enamine
C=O ke lone pairs would repel
Ahmm I'm afraid In not
do you know someone who is
and can be found online at this time
I feel like lancelet is
But he might not be online rn
You post your question @V-Tone
Hardcore can do it well too
it was based on statistics
I hope
i have an interview tomorrow
so needed some info on that
I have done a course in statistics so I guess I can help
Depends on what kinda question it is
Post it anyways
@V-Tone @Enamine should i close this ??
u guys can create new thread
Yeah yeah just told him to do that
Close it
I have dmed you as well enamine
alr
+solved @Enamine
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thanks