I
iTeachChem2mo ago
nori

goc scq

given ans d why is c wrong
No description
39 Replies
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Sephrina
Sephrina2mo ago
deuterium is less stable than hydrogen it has an extra neutron
Prasan
Prasan2mo ago
D bhi batana ha kya?
nori
noriOP2mo ago
but what about +I effect +H is same in all
Sephrina
Sephrina2mo ago
well kyunki d me extra neutron hai to thoda alag hoga im not sure on this but hn alag hona chiye
nori
noriOP2mo ago
yeah.. cuz isn't it the correct order? radical on double bond is unstable right.. and first has more conjugation
Sephrina
Sephrina2mo ago
@Enamine any idea on this
nori
noriOP2mo ago
oh okay..
Varun_Arora
Varun_Arora2mo ago
Hmmmmmmm Ek second
Sephrina
Sephrina2mo ago
2 sec lelo
Varun_Arora
Varun_Arora2mo ago
Bruh I'm clueless at this one Kuch khaas difference aayega bhi nahi
nori
noriOP2mo ago
and what about opt D?
Varun_Arora
Varun_Arora2mo ago
Option d seems simple enough Radical on a phenyl Sp2 pe radical Not good (bent's rule)
nori
noriOP2mo ago
Yeah so it is the correct order of stability right the opt says incorrect
Varun_Arora
Varun_Arora2mo ago
Yeah it should be
nori
noriOP2mo ago
and the q asks correct i feel like it's an ans key error and c should be the right one?
Varun_Arora
Varun_Arora2mo ago
There is something weird about this one Maybe I'm missing something There could be an error as well
nori
noriOP2mo ago
which one will be more stable in this case? Do we look at the minus charge or the fact that it is aromatic? Like which will dominate
No description
Varun_Arora
Varun_Arora2mo ago
Vo c vaale me to I'm clueless ngl
Sephrina
Sephrina2mo ago
kyu?
Varun_Arora
Varun_Arora2mo ago
Hyperconjugation ho nahi sakta
Sephrina
Sephrina2mo ago
aromatic
Varun_Arora
Varun_Arora2mo ago
And inductive vaise bhi itna weak hai Plus H ka D karne se inductive pe khaas farak nahi padta kuch
nori
noriOP2mo ago
but acc to the key the second one's more stable they said that it's cuz - charge is localised in the first one
Varun_Arora
Varun_Arora2mo ago
Phenyl pe charge something you desire tbh Yeah To keep the Aromaticity It remains charged
nori
noriOP2mo ago
yeah plus sp2 pe negative
Varun_Arora
Varun_Arora2mo ago
That charge is very well localised
nori
noriOP2mo ago
is good right so does it become less stable cuz of that
Varun_Arora
Varun_Arora2mo ago
It is but better be delocalised
nori
noriOP2mo ago
why dont we look at the fact that it's aromatic
Varun_Arora
Varun_Arora2mo ago
Charge ek jagah rahega to it creates instability
nori
noriOP2mo ago
and how do we know which one domiantes ah okay
Varun_Arora
Varun_Arora2mo ago
See Aromaticity reh Rahi hai But charge doesn't spread That's the problem
nori
noriOP2mo ago
hmm okay i get it now
Varun_Arora
Varun_Arora2mo ago
Let me look into that c option wait Never encountered that not kidding
nori
noriOP2mo ago
okay
Gaurav
Gaurav2mo ago
okay so if there wasnt the unpaired electron we could have easily applied the aromaticity 4n, 4n + 2 rule right?
Varun_Arora
Varun_Arora2mo ago
Bro inductive effect is making me question my existence everyday Gotta get this shit done fr today

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