53 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.pls explain your thought process
Yo
You tried partial fractions
?
not applicable
these arent polynomials
Take expression = $$[(Ax) /(2x^2 + 3)] + [B/x-1] + [C/x+1]$$
Enamine
Ohhh
That 1/2
It wasn't visible earlier
Sorry
np np
Open it up
We could do some trig sub here I suppose
i actually know what to do but i dont have a logic for it
like "why" this
It's a shorthand
You see
Squares under a square root
You think of trig identities
That gives you a hint as to convert into a useful form
There must be some other method too
But this is the most conventional
And frequently used
x=sectheta ??
tan would work better no?
tan^2-1 would be harder to deal with
@hardcoreisdead
can u send ans
After converting it to x^2 + a^2
Naah not it in that
im getting something i want to cnf whether its correct or not
First open it
indefinite pakcage page 42
alr
Convert it to the x^2 + a^2
ok trying
Such a smooth convo lmao
ek sec ismein kaise aayega
root( degree 4 )
i converted the numerator to 1/5* [ (2x^2+3)-2(x^2-1)] then it was coming standard integrals for both iirc
Further substitution
nah nvm
t2 ko x maan ke and stuff
Sorry
X square to t maan ke
Whatever
aur bura ban gya
yeah took to long to solve that
there would be a better method
avhaa
Isme I suppose something else should be there too
2 baar substitution karna pad raha hai
Ek to mai just utha hun
I'll try this myself thodi der me
@Enamine x^2=t wont work cuz 2xdx = dt . numerator mein sirf dx hai
Aaah I see
Does the answer have arc sin etc?
nah
Weird.
i might be *one of the * answer
Haha yea if you get arc sinh or arc tan h
Then trig sub hai.
But waise for what exam are you doing these qs? Or just for fun
Cos these can only be done if you know the substitution. Too much rigour otw
primarily adv
yeah
x2 −1=tan^2( θ)
bro someone teach me latex here
$x^{2}-1=tan^{2} \theta$
Real potato
Like this sir
$x^{2}-1=tan^{2} \theta$
ah dolla dolla
sorry LOl
U diidnt hve tk write that lol😂😂
yea sometimes you write \
two bwd slash
sometimes two $ wasnt sure which
Yup
thanks :D
$ is for entering maths mode
((2sec^2t+3)(tan^2t))
correct.
and dt = sec t*tan t, so tant gets cancelled out
wait why 2t
uske bsad another round of sub tan t = u, then yhou get sin h-...