24 Replies
@Apu
,rotate
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Is the answer "does not exist"?
Nope
0 times infinity kinda ban Raha hai
4
Some how
Aaah I see
I did this wait
0 times infinity is indeterminate?
I guess yeah
Alright
Even putting values directly
1/2^x
That gives you something positive
Close to zero
The other one
Gives you 1/something positive
That something positive is very close to zero
Idk why am I not able make something out of this uhh
1-2^(-x) tends to xln2 as x tends to zero
Similarly applying binomial approx. In denominator gives you 2(x/8+1)-2=x/4
Toh xln2*4/x
=4ln2
Heh?
Is that a thing?
Write it as -(e^(-ln2.x)-1) which tends to -(-ln2.x) which tends to ln2.x
As x tends to zero.
Right right
What about the
tanx wala term
Wo to 1/x aara
tanx tends to x and then use binomial approximation.
Can I fr use that?
Feels very out of place to use
Yo can you send a full written solution once?
Assuming you get the x.ln2 part. As for the denominator 2(1+x/4)^1/2-2 tends to 2(1+x/4.1/2)-2=x/4
(Taking only the first term from expansion of tanx because it dominates over other terms)
And xln2/x/4=4ln2
Wait can you point out where is the problem?
the tan wala expansion
what bhai ye 1+x/4 kidhar se aa gaya kya hora
4ln2 to aa gaya
tanx is tending to x right?
(Taking first degree approximation kyunki waise bhi x^3 wagera term become too less in comparision to x)
Uske baad root se 4 bahar nikalo
Then use (1+x)^n wala thing.
oho
+solved @SirLancelotDuLac
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