Limits diffrent method confirmation
The 2nd image is giving answer the 3rd one is giving 0 is it all correct?
Also how does a single limit have diffrent values?
18 Replies
@Apu
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Welp
, rotate
It's this correct?
yaar aana toh zero hi chahiye
something fishy is going on
haan kara to theek hai
2nd is the marked answer and wo bhi galat nahi hai
but 0 bhi sahi hai
diff approaches diffrent limit value??
graph se toh 1/2 hi aayea
Nuh uh. A limit can't give 2 values (unless it doesn't exist). The approximation taken in the third one is incomplete. Since the denominator is of x⁴, we have to take into consideration all the terms of x until the power of 4 (which means the second term in expansion of tanx is to be taken)
(Tldr: Approximation sahi se lena is very important in limits, especially when 0 by 0 kinda stuff)
wait what
damn
but in some other questions when we did this, there wasnt any problem in that. uska bataoge
Kyunki there first degree approximation worked. For example Ek hai (tanx-sinx)/x^3. Isme first degree approximation isliye nahi laga sakte kyunki expansion ke x^3 wale terms are significant w.r.t denominator and hence bring a change about the result.
Similarly if the question was (tanx-sinx)/x^2, now the first degree approximation would work since the second terms of expansion (the x^3 terms) are much smaller w.r.t. denominator (x^2)
Yar vo significant ka kya mtlb ga, significant wrt drnominator
I get it okk
Goes back to how these were derived in the first place
fine fine sorted ig
+solved @SirLancelotDuLac
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