magnetic pressure
what pressure does the lateral srface of a long solenoid with n turns per unit length experience when a current i flows through it
27 Replies
@Gyro Gearloose
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dekhta hu isko
puchna pdega teacher se apne
kabhi doubt nahi aaya ye
imma consider it as a cylinder, u can multiply by n for solenoid, btw do u mean later surface as the curved walls of solenoid?
thats the only surface so yeah ig
hows the currnt flowing? along the cylinder or along curve? or is it a wire passing throguh its axis?
solenoid hai ....
i confused myself by assuming it as a cylinder, great.
hua kya
do you have the ans to this? like can u confirm the ans
or is it just a general doubt
its B^2 /2mu where B= muni
yeah like that's the gen formula of magnetic pressure
like electrostatic pressure was sigma^2/2epsilon0
here we have B^2/2mu0
you can use it for all cases ig
whi toh baat hai, can you ?
i basivally want proof wahan bhi kaam chal jayega uss se
oh okay
you can.. cuz we pretty much did the same thing for electrostatic pressure
but yeah, proof idk will have to try
haan bas proof chahiye
Proof for that formula requres some advanced physics such as vector/tensor calculus and maxwell equations afaik
i did prove it for cylinder tho ...
Yea let me try if theres another method
I did this for solenoid, ig u can prove it for some shapes but in any general case u need maxwells equations
can u share something along the lines of this
,rotate
b4 i proceed i shall mention that the magnetic field due to a current carrying wire exactly on its wires surface is acctually the avergae of inside and outside filed of the wire which is (u0 * I)/4 * pi * R. its jut like electric field just at the surface of the conducting shell which is 1/2 * kQ/R^2
sorry whats the relevancy here
Nvm my mrthod aint working fot current carying wore
Wire