34 Replies
@Moderator bot down
Mere doubt mein bhi nahi aaraha
tu hi karde fir
Definite hui nahi meri abhi
Uski khaas zarurat bhi nahi
@Prachi try?
@Apu
bhai aise particular tag mat karo
unhono dusra bhi kia tha so i thought kardu
wont do again 🙏
still buddy
Bhai....
Mera dimaag hil gaya isko karke
Kuch bhi samajh nahi aa raha hai kya karna hai
Sab kuch try kar liya
sinx ko kholne ki, kuch substitute karne ki, trigonometry laga li
Lekin kuch nahi hua
Ek baar kal sir se poochti hu ye wala varna mera man shaant nahi hoga
i do have the soln btw
i just wanna know "why" would u do that
not telling cuz then the thought wont be original
its some substitution btw
the answer is 0
or 1
:p
in all seriousness, if you take t = 1/x
Yes sir, mera bhi answer kuch karke zero aa raha hai
why
whats the thought process behind it
odd power, odd function
the two thingies will negate each other out.
1/x -x is changing to x-1/x (by doing the substitution)
iTeachMath (woo)
i have seen this before dude
hard to come up with this on the fly
it indeed is
i tried and my goodness, kuch ni pta chla
@hardcoreisdead bhai hua ye vala? X ko 1/t daalke hi karna ha kya?
yep whi treeka hai
aur koi toh nahi mila
Bhai mera to vese bhi nahi aara
@SirLancelotDuLac inputs ??
bruh
lets wait for his reply
iTeachChem sir's method as above ☝️ .
Sub x=1/t and do stuff. This is a useful thing to do when you see things of form like 1/x-x or smth.
can u explain what part of question gives the idea of x=1/t
The x-1/x term. If you keep x=1/t you get -(t-1/t) term, and since sine is odd, it might lead to a result like I=-I, giving us integral being zero.
bruh am getting I=I
x=1/t
dx= -1/t^2 dt
You forgot to change the bounds from 0 to infinity to infinity to 0
so the minus are neutralied
ohhhhhh
damnnn
right
To revert the bounds you must again put a -ve sign.
yeahh
Ik this because I did the same error myself for 10sec 😭
lolol
nice ques
+solved @iTeachChem @SirLancelotDuLac
Oh shi
Nice one
To be closed when bot is fixed
+solved @SirLancelotDuLac
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