30 Replies
question boils down to find moi about x axis ig
cant find out tho
@Moderator physics ping
@Apu
Ig it should be just 2/6 MR^2
thought so too but not in options
Naah 2/3
ha shi kaha
Mass adha krna bhul gaya tha
ans toh fir bhi ni ayaa
Ye aara brother
options dekho brother
None of these :kekw:
woh nahi hai ans lol
Im getting mr^2/3 now
:aah:
i think mr^2/3 hi hona cheye yr
I.pi.r².B ho gaya torque. (Along x axis)
System ka moi about x axis ig is 2/3mr²-m(dist. of com from origin in figure)
moi kaise likha
Mera wala ans aara hai na
Torue is along x axis toh angular momentum is about x axis.
Uske according find the moi.
Which I can't figure out how to do ;_;
exact same problem lol
Shouldnt it be half of that of sphere
Answer to vese usse bhi nahi aa raha hai
Okay, I'm so dumb, I didn't notice. This will have same moi as a spherical shell ig.
thats wht i thought and with half the mass it turns out to be mr^2/3 ?
ans is A my guys
it comes when u take moi about com of the shell
idk why tho
Its not hinged or anything so obv it will rotate abt its com which u cn find using knows formulas and u can find moi abt that axis which passds through com similarly using parallel axis theorem
Mass would be m itself na.
Cause the mass of the full sphere would 2m.
half sphere ke lie bhi to divide by 2 krna pdega
Mass toh m hi hai na sphere ka? Imagine ki main sphere ke har ek point ko 2 equal halves mein todke usse circular face pe mirror kar doon, toh you get a full sphere of mass m while radial distances of all the (net points) remains unchanged.
oh yeah i messed up lil bit
hmm makes sense
+solved @integralofe^2v
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