Integration 1

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@Apu
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SirLancelotDuLac
Ig sub x=pi/2-t Kyunki then you'll be able to simplify (1+sin(x)) term and (1-sin(x)+cos(x)) term to half angles. $\frac{e^{\frac{\pi}{2}-t}.sin(t)cos(t)}{4cos^{2}(t/2)(2sin^{2}(t/2)-2sin(t/2)cos(t/2)}$
TeXit
TeXit4w ago
SirLancelotDuLac
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SirLancelotDuLac
Write the numerator ka sin as 2sin(t/2)cos(t/2) Some terms get cancelled and you get $\frac{e^{\frac{\pi}{2}-t}cos(t)sec^{2}(t/2)}{4(sin(t/2)-cos(t/2)}$
TeXit
TeXit4w ago
SirLancelotDuLac
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SirLancelotDuLac
Write the denominator ka term as sqrt(2)sin(pi/4-t/2) and numerator mein cos(t)=2sin(pi/4-t/2)(cos(pi/4-t/2)
Prasan
PrasanOP4w ago
mai karta try isko @SirLancelotDuLac end mein kuch simplify hoke bach gaya bhai humne thoda zyada soch lia (sinx-cosx)^2 = 1-2sinxcosx 2sinxcosx = (1-sinx+cosx)(1+sinx-cosx) +solved @SirLancelotDuLac
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