12 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.this is what i got for f'(x)
i did f(g(x))=x
f'(g(x))*g'(x)=1
so i cant find out f inverse of x at x=0
Do g(f(x))=0
f(x)=0 at 5pi/4
So plug that in g'(f)f'=0
isnt g(f(x)) = x
how did u figure out f(x)=0
the function i gave above is f'(x)
Oh sorry mb. Meant the same.
Integration of something from a to a is zero na.
So just find where sin and cos are same in given range.
ok so g(f(5pi/4))= g(0) = 5pi/4
f'(5pi/4)*g'(0)=1
f'(5pi/4)= -2e^-1/root2
aise toh galat aa rha hai
@SirLancelotDuLac
Consider g'(f(x))f'(x)=1, then,
g'(0)f'(5pi/4)=1 and g'(0)=-1/2(e^(1/sqrt(2)))
So ig its neither B or D?
the key does say D tho
oh nvm it doesnt
the key is wrong
just needed your confirmation
+solved @SirLancelotDuLac
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