93 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.if im thinking correctly
how do i calculate that smol area
@Phalawor only circle se flux hoga net
Na Wait
Wait wait wait
think it thru
i think
wo blu wala region
hi flux produce karega
Hmm wahi karra
Jaldbazi me lik diya tha
yeyeye mujhe bhi initially yahi laga
then thought about it
lol
@Phalawor yehi hoga bas projected area ellipse aayega
in the scenario of cone not tilted , is there electric field below the base
kya??
kyuu
kya
Yeahh
It's just same as projected area of circle
Try it practically if can't visualise
arey but what about the curved surface
ellipse hoga
ok i get it
what about cone ka curve
what about 0
??
like
uhm
0 fluc
there no charge given
could that be possible
cuz if im imagining correct
every line going into the left ka surfeace
can make it ot
the right wala surface
(i dont have answer key)
is it D?
BRUH
BRUH
ðŸ˜
anyway
what did you think
to make the situation easier to think
instead of tilting the cone
tilt the electric field
even if i tilt the electric field bro the projection is just too weird
just an idea
still working it through
also
this??
no??
@Phalawor trust me or try for one
kaise try karu
use flux in closed shape is 0 in ext field so this js boils down to finding flux thru missing cicrcle (base of cone) so its D ig
Yeah
bhai kya
closed shape me did we already not consider the base ka circle??
that it has no flux to contribute
??
Shij hai..
Ye nahi ho sakta kya?
,rotate
like this we ultimately want flux s1 and s2 only
And the net flux becomes 0?
OHHHH
OHHHH SHIT BRO
AREYYYYYY
it isnt a closed shapee
Hahahaha okokkdhdidvfeejwz
Arey why didn't I think of thai
wait
phi s1 + phi s2 nikaloge kaise
we cant, thats why we find phi c
han fir woh kaise aayega
which s equsal to it
Waah bhai
Itna fundamental tha phir bhi nahi hua
It's simply the vertical projection
vertical projection dA sin60 nahi aayeg
it happensðŸ˜
oh ha
wahi
ohdhdsnaoi
nahi
30 hai
arey
yaar
hatt
haa ye sahi hia
angle 30 hai naaa
han..
,rotate
Acos60=Asin30
we take hori comp
oh shit mein vertical lene laga
does this work
ek sec vertical nahi lena chahiye
E dot A
Parallrel comp
to field
what
parallel??
whyy
Field goes through sin component
parallel me to
w8
mb
0 flux hota na
flux vector
bahar ki taraf hoga
not in
nhi im right
flux doosri side hoga bro
parallel so tht area vector perp to field
surface shape se
@Phalawor E ke 2 components nikaal kaam khatam...
outgoing hota hai a
aur A?
A?
Area?
nvm
im being stupid
area vector perp krna he
area vector field ke perpendicular ho gya toh zero nahi ho jayega flux
but shape ke to outgoing hota hai na
bro how is flux even passing through this surface
...
E.dA
closed surface ke outgoing hoga na area vector
ye jo aapne bheja
EdA cos90 = 0
into the shape ho gaya
mention me as well agr nhin hua ye toh
actually
hes right
cos(angle between E and dA vector)
which is clearly 60 here
mb
AREA VECTOR HUMARE SHAPE SE TO OUTGOING HOTA THA NA
SHAPE KE ANDAR THODI JAEGA
@Phalawor
Kisne kaha
Area vector manna mere haath me hai
out hi to he😠see arrow
oh sorry
@integralofe^2v i still dk if my method of tilting the field is correct
im sleepy ig
sorry
ill look later wait
Like how
bharry dangaras
unable to be interpreted
got it guys
tanks
+solved @integralofe^2v @hardcoreisdead @SchrodingerBilla
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