29 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2...
to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
could you please post the original question?
It was given to us in class like this
This is the only info ive checked 2 times
you gotta use mu (y) sin theta = constant>
Not mu sintheta
What will be the diff if i write that
ye sab tumhare syllabus me nahi hai :)
if you havent learned it ditch
Physics Ninja
YouTube
Fermat's Principle: Finding the Minimum Time for Light to Travel
Physics Ninja looks at Fermat's Principle using 3 different methods.
In part 1 a simple numerical example is presented. In part 2 (time: 14:42) we use a calculus approach to find the minimum time and show that it corresponds to Snell's Law. In part 3 (time: 19:46) I show how to solve this problem using the Euler-Lagrange Equation.
its math heavy
There should be another way then, thats why our sir has given it to us
Hai sir not directly but it's application
if you use the parabola eqn, uska slope = tangent = tan theta, you can get sin theta from there.
mu = m0 (some constant) times this sin theta :)
tan theta = dy / dx = 2a/y
Ive done that in my working that ive posted
but again, this is def not in syllabus lol
oh yeshave
that sthe answer
:D
before the last line
mu 0 x rt (y^2 + 4a^2)/2a
thats mu (y)
Smjh nahi aaraha ye kya likha ha
just coaching things
how to write code here
forgot
:D
I also dont know
Yes sir, but its concept is useful to do questions...
bottom right

bro
come on :D
it is rot that coaching people teach
unless there have been qs that have come from this idea anywhere yahi hai :P
the actual thing to teach is that time taken is least.
Acha aise kehrahe
Yehi toh kehera sir
ie differential eqn
Sahi to lagraha ha ab
Kal answer confirm karke btata hun
The concept that light choose least time path
+solved @iTeachChem
Post locked and archived successfully!
Archived by
<@1382187168230936577> (1382187168230936577)
Time
<t:1754835654:R>
Solved by
<@1035556259417571408> (1035556259417571408)