magnetics 2

No description
27 Replies
CorrodedCoffin
CorrodedCoffinOP2w ago
,rotate
TeXit
TeXit2w ago
No description
iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
CorrodedCoffin
CorrodedCoffinOP2w ago
ig trajectory should be the green path
No description
CorrodedCoffin
CorrodedCoffinOP2w ago
it would mean the velocity vector turned by an angle of pi/3 the angle between final and initial velocity vector maybe i am missing smthng
integralofe^2v
Shud be smth like this
No description
CorrodedCoffin
CorrodedCoffinOP2w ago
why would it return
integralofe^2v
The gap is too large at end so it will follow circular trajectory
Sephrina
Sephrina2w ago
uska aise to calculate karna padta hai kya ki apan surely bol sakte hai?
integralofe^2v
I can calculate let me show
Prasan
Prasan2w ago
Calc karke bhi vahi ayega
Sephrina
Sephrina2w ago
hn vaise info to given hai
CorrodedCoffin
CorrodedCoffinOP2w ago
kaise aayega calc karke
Sephrina
Sephrina2w ago
To ho jayega
CorrodedCoffin
CorrodedCoffinOP2w ago
oh.
Sephrina
Sephrina2w ago
are seedha formula haina r wala usko apply karke
Sephrina
Sephrina2w ago
hnn ye wala mv/qb se nhi kar sakte?
integralofe^2v
U can find radius using tht only ig?
Sephrina
Sephrina2w ago
Hnn
CorrodedCoffin
CorrodedCoffinOP2w ago
@integralofe^2v C shouldve been 6root3 ??
integralofe^2v
Yes
CorrodedCoffin
CorrodedCoffinOP2w ago
if point of release is origin then max x cord is 21 m ?
integralofe^2v
Correct
CorrodedCoffin
CorrodedCoffinOP2w ago
thanx +solved @integralofe^2v
iTeachChem Helper
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