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@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.36kph = 10 m/s , 54 kph = 15m/s
matlab motorcycle is accelerating for 10s and car for 30s
it is possible that overtaking occurs between 10<t<30 i.e when bike isnt accelarting but car is
10*10/2 + 10(t-10) = 1/2 1/2 t^2
roots of this quad are 20 + - 10 root2
both of which are not included in desired range
so we scap these values and determine that overtaking must occur t=30 ie after car and bike both are done accelarting
is there any method to come to this conclusion whilst avoiding this calc
Yeah
At t=30sec you can check that cycle has travelled 250meter
And car has travelled 225m
So we can conclude ki overtaking t>30sec ke baad hui hogi jab dono constant velocity p aagye hoge
got it thanx
+solved @Shreyaaa~
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