9 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.yo smal thing
title me put in the name of the topic and chapter
Did you try doing quadratic in y where y = 3^x
Roots then become
a+- rt (a^2 - 4(3-a))
While thing div by 2
Uske baad fir internal thing you can factorise to be a + 4 times a-3
sir ye step samajh nahi aaya
This will be equal to 3^x
Which has to be positive
okk
ek baar try karta
It gets a bit complicated after that. You can kinda figure it out by seeing that the eqn in y is that of a parabola.
But thoda trial and error helps putting f(0) f (1)
Yea sure, try off :)
(2,3)
take 3^x as y , and then a negative sol for x means x<0 hence y lies between 0 to 1, then a > = y^2 + 3/ y+1, differentiate this function to see its nature, you'll find that its a decreasinf cuntion between 0 to 1 , hence the range is simply its endpoints, thus y tends to 1 minus and zero plus