rotation

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21 Replies
iTeachChem Helper
iTeachChem Helper•2w ago
@Gyro Gearloose
iTeachChem Helper
iTeachChem Helper•2w ago
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Shreyaaa~
Shreyaaa~OP•2w ago
c wla ye wla point kese find out karu
flower
flower•2w ago
ground pe hoga ig cuz the point at ground is at rest to 0 acceration
Shreyaaa~
Shreyaaa~OP•2w ago
nikalege kese
flower
flower•2w ago
R,0 ye nahi hoga kya idk im trynna cheese this one
Shreyaaa~
Shreyaaa~OP•2w ago
wht😭 you forgot something
flower
flower•2w ago
nah idk kya hoga then
Shreyaaa~
Shreyaaa~OP•2w ago
centripetal acc r,0 par acc zero thodi hai centripetal hai waha
flower
flower•2w ago
sahi baat hmmmmmmmmmmmmmmmmmmmm 0.0 idhar to arey nahi
Shreyaaa~
Shreyaaa~OP•2w ago
pata ni yar dekhna pdega
flower
flower•2w ago
ye to ajeeb hai
Shreyaaa~
Shreyaaa~OP•2w ago
hai to :shocked:
integralofe^2v
integralofe^2v•2w ago
R=3 and theta=30?
Shreyaaa~
Shreyaaa~OP•2w ago
yyp
integralofe^2v
integralofe^2v•2w ago
heres how i did it btw
No description
Shreyaaa~
Shreyaaa~OP•7d ago
me isko kl dekh lugi ek br aap pls explain kr skte ho apne kya kia hai?
integralofe^2v
integralofe^2v•7d ago
Firstly did u get how i found acceleration of com? Basically it says non slipping which means v of COM=R * w and if u diffrrentiate both sides wrt time then u get a of COM=R * alpha
Shreyaaa~
Shreyaaa~OP•7d ago
yeah i get it i got the same using iaor
integralofe^2v
integralofe^2v•7d ago
Okay now i assumed a random point at radial distance r and angle theta and i wrote down all the accelerations acting on it ( centripetal , tangential , acceleration of COM) and then yes equated the vertical and horizontal components so tht they cancel each other so hence net acceleration at tht ppint is zero
Shreyaaa~
Shreyaaa~OP•7d ago
oh alright i got it

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