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@Apu
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Each bracket is an AP with c.r.=-2/3, simplify the nth bracket to get something
After that the sum of above terms is sum of another g.p.
general term bhi kya hi banegi iski 💀
aree ye toh mains mei aya hai shayad mere module mei tha
do you still want the sol?
my bad i forgot about this one ill try it once more day and then ill let uk
Oh yeah pyq hai idk mains ka hai ya adv ka
But pyq hi tha
ye
Each bracket is a gp na
take x = 1/2 and y = 1/3
each term is a GP whose common ratio is -y/x ig
and its in the form of x^n(-y)^0 + x^(n-1) (-y)^(1)................... x^0(-y)^n prob
there's this formula for sum of such sequences = (a^n+1 - b^n+1)/(a - b) [ here a = x, b = -y -> can also be derived easily] ........ using this you'll probably get (x + y) common in the denominator and the rest it pretty doable ig.
Im not able to understand, could you write it down on paper and explain?
nvm this was eazy que adding (1/2+1/3) was the key
answer's 1/2?
Yeah