79 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.What is virtual work method?
sum (T.a) = 0 cuz work done by tension is zero
,rotate
same string different tension
Wo pulley ke upar likha hai
hai to fir bhi same string hi
Pulley ke upar 2T laga to uske upar wala string 2T tension balance krega na bro
blue and red are parts of same string right
agar blue pulley par tenion T krdi to uspe net force nhi aajyega:uhh:
par same hi string mein do alag tension kaise hai
Wait
I think
Ye wo wala que hai
Jaha virtual work method fail ho jata h
basic se krna pdega isko ig
aisa bhi hota hai kya 💀
Ha na
Har jagh nhi lagta ye method
god damn
tumne virtual work bola to mene laga dia bina soche samjheðŸ˜
meine toh aajtak woh ajeeb se method use hi ni kia
block x neeche pulley 2x neeche blah blah
Yahi krna pdega :uhh:
:aah: mujhe bhi bilkul pasand nhi lol
ðŸ˜
side ques
in dono cases mein constraint relation same aayega na
acc of m = acc of M sintheta
Iska ans g to nahi? I remember jaha ye method nhi lagti waha Tension zero hoti hai
Blocks g se niche aate h
Shyd yehi hoga ans check krke batana
kiski accn
m1 m2
g
Acc
yes
Ha fir ye wahi case hai:uhh:
boluga to nahi par is case ko yaad rkhna tension zero hi aati hai
kya kya yaad rkhu 🥀
yeh bhi batado kaise aayega
@Real potato
dekhta
one method i understand is displacing wedge x backwards so block falls y
ek yeh bhi hai but i dont understand accn aise hi kyu li
oh wait i do
ax and ay lia hai
ax toh parallel to surface so doesnt matter
Aisa islie
Kyuki
Along the surface
Same acc hona cheye
is type k que to relative se krlia kr usme confusion kam rehti
@Real potato yeh bhi virtual work se nahi hoga kya
ye to ho jayega
han
ho gya
@Real potato original ques (T=0) wale mein accn of blocks toh samjh gya
pulleys nahi samjha
uske lie wo dekhna pdega string length🥀
wait ek br krke dekhta
P2 ka to g hi hoga warna rope slack ho jayegi
@hardcoreisdead
ap2 = a m2 = g ?
like m2 ki g hai islie p2 ki must be g too right
Yeah this
p1 thoda sa dekhna pdega
P2 ka acc zyada kam hua to rope slack kregi na
han
cant we use that a1+a2/2 thing
p1 ke lie to ab wo length of rope wli cheej likhni hi pdegi🥲
this
for p1?
Ig so but wo upar jo string lagi hai p1 pr
uska kya
ye nhi lg payega yaha formula ig
why
Wo string ka acceleration kese nikalege
agar p2 ke upar wala string g se niche jara hai to wahi string p1 ke upar bhi connect hai na
Wo g se upar jana cheye :/
kyun
g se neeche jayega
oh
.
well
But ye ho nhi skta
Agar ye bhi g se niche jara hai
Pura system hi to g se chala gaya
hn
Sbse upar wale pulley ke doni string g se chle gye to kese kaam chalega
:aah:
hnnn
karle bhai usse string constraint laga kar
W ques
ðŸ˜
beth kar likh wo x1 x2 or kro diffrentiate
full majdori que
ok so final verdict is m1 m2 p2 all go down with g
and p1 up with 3g
p1 ka agya?
:shocked:
hn
W
upar hi ja rha hai na par
wo tumne jo positive negative maan Ke differentiate kia hoga
Usse dekh na
something seems fishy
@Real potato
baki sab to theek lgra hai bs ye xp2 ko differentiate krke
2g
Kese
hanne to g nikala tha na p2 ka acc
printing error
l= x-xp1 + 2xp2 likhna hai
Ah i see
fir bhi dirn ajeeb si hai
@hardcoreisdead
I got a better way
To find Acc of pulley P
I mean its the same concept but less tds
yeah tell
So basically what we are gonna do is make every stringh length constant with the given velocities
And then we’ll diffrentiate
wait ill write it on paper
Page khtm hogya thoda sa messy hogya but ig its understandable
We are getting -3g so acc of pulley p is downwards
@hardcoreisdead samjh gya?
,rotate
got it man
big thanx
+solved @Real potato
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