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@Gyro Gearloose
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Eqn toh aa gyi par solve nahi ho rhi
ax = Asintheta hai not ay
wrt wedge it has to go down the incline and wedge will go towards the left due to common normals component
it = block
Ans is mgsinq/M+2m(1-cosq)
?
@hardcoreisdead
yus yhi hai
Ts is from irodov yeah?
ye to cengage hai
Irodov me bui tha aisa same
um mene dusri approach se kia hai
Tumhari se bhi ho jyega but it will take too much calculation and im out of it🥀
ig haan
lala aadat daal lo calc ki
mains is not far now
even adv is calculative now
Baat to thek hai yar pr is type ke que ke liye relative acc wli approach is quite fast
Ussi se kia mene
@Real potato meine relative se bhi try kia but woh toh aur galat aa rha . Why ???

Normal kyu eqn kyu likha raha hai
Ek eqn sahi banai hai
Ek constraint ki likh
Or ek puri system par net force tension ki
ruk likh k bhejta
galat kya hai par
T=Ma+m(a-arel costheta)
Or ek constraint ki
In teen se ajyega
Dekhta dinner krke
nvm got my error
Normal calculate krna bhari pad jayega
Phele islie acc nikala
Net force eqn se
Fir normal asan h agar cheye bhi ho to
last eqn galat thi
kya galti thi
Nsintheta=Ma wla?
haan
T lia hi nahi 💀
:aah:
getting back to this
iss method se kaise hoga
Wo ay ya ax= Asintheta
That is the constraint eqn na
han
i lack one relation
Yaha bhi net force eqn to likh hi sakta hai na
Wo likh de
Net force=T
ax ay T N a
5 unknown
i have 4 eqn
yeh kaunsi aai
Net force in x direct is T
To usko Ma se equate kr
Sare x direction ka acceleration
MA+max
Jo bhi tera x me acc ara hai
.
Like this
Ye relative wla tha
Ground frame wala likhna pdega
Talk in reference to this

Mein x and y axis alag lia hI
T=MA+m(ax—A)
ax mtlb jo real wala x axis hota uske along wala acc
tera wala nhi
Cause ham Direction ka force likh rahe ba
That is Tension
Tere wale x direction me or bhi force aajyega mg Ke components n all
Pseudo force diya hai block ko?
+solved @Real potato
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