emi- lr circuit
The currents through the inductors won't change right? Then what exactly is the heat dissipated? From what I can see the current through the first resistor should increase from I to 2I? And ig direction will also change
12 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.its a mix circuit no current wont change if it was purely series
also how is this series??
parallel haina
current is splitting
before 2L
achcha formula wo parallel wala hoga
after opening decay of current in LR circuit
total heat loss = total energy stored in inductors
yems yems yems
i should note that down
1/2 * L (2i)^2 + 1/2 * 2L i^2
so 3Li^2 ig
isnt that just energy conservation
i keep forgetting it
;-;
smol brain
hmm happens lol
Oh okay... Right. I was confused about the heat dissipation wala part.
TYSM @hardcoreisdead
+solved @hardcoreisdead
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