5 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.this is the scenario at t=3R/v right
f=R/2 , u = -R thus v= R/3
longitudinal magnification = - 1/9
o is object m is mirror i is image Vo = -v/2 i cap ; Vm = v/2 icap Vom = -v icap Vim = longitudinal magnification * Vom = v/9 icap Vim = Vi-Vm => Vi = Vim + Vm = 11v/18 icap longitudinal magnification means along the axis and tranverse perpendicular to axis mb ppl am high ig +solved @vj25_
o is object m is mirror i is image Vo = -v/2 i cap ; Vm = v/2 icap Vom = -v icap Vim = longitudinal magnification * Vom = v/9 icap Vim = Vi-Vm => Vi = Vim + Vm = 11v/18 icap longitudinal magnification means along the axis and tranverse perpendicular to axis mb ppl am high ig +solved @vj25_
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