optics 3

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@Gyro Gearloose
CorrodedCoffin
CorrodedCoffinOP4w ago
,rotate
TeXit
TeXit4w ago
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iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
CorrodedCoffin
CorrodedCoffinOP4w ago
ismein jeep ke dimensions toh die nahi hai First part of longitudinal magnification leke hi aayegaa Second part mein kya karenge like should i take transverse or longitudinal magnification @Real potato
Prasan
Prasan4w ago
Pehle part ka answer batana
CorrodedCoffin
CorrodedCoffinOP2w ago
21 m/s i cap
Prasan
Prasan2w ago
Dubara krta isko kaafi time hogaya Aur bata hardcore kesa chlra. Syllabus hogya?
CorrodedCoffin
CorrodedCoffinOP2w ago
kahan bhai revision bhi ni ho pa rha
Prasan
Prasan2w ago
Same bhai. School ke paperon ne tang kr rkha hai
integralofe^2v
ud need the dimensions, u can directly do like this, btw u dot is velocity of object wrt mirror and v dot is vel of image wrt mirror
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CorrodedCoffin
CorrodedCoffinOP2w ago
m= f/f-u dm/dt = f/(f-u)^2 * du/dt = 1/10 * 1/100 * 21 why is this wrong
integralofe^2v
du/dt is 1 since here u take velocity wrt mirror
CorrodedCoffin
CorrodedCoffinOP2w ago
ohhh right makes sense +solved @integralofe^2v
iTeachChem Helper
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