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@Gyro Gearloose
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integral B.dl=mu_0 times I + epsilon_0 times displacement current iirc?
Integral B.dl is just B(2.pi.r) as we consider circular loop and displacement current is given
I is zero here
Just plug in the values and you're done.
vo to tab hota na jab centre pe ho
Axis pe line nhi kar rha point
We take the loop as a circle with axis same as drawn in the figure
To vo 4 cm upar ho ya axis pe vo same hi hoga?
hume aise diya hai solution but kuch smj nhi aaya
j ki kya jarurat hai
Wait Imma write this out
hn sure
i (enclosed) likhne ke liye
unne phele j nikala current per unit area
Fir 4cm me kitna area ayega usse multiply kr dege
par kyu jo diya hai usme kya dikkat hai
Wo total current hai
to?
Plate radius 0.1m hai mtlb 10cm to 10cm tk ke area me se utna current pass hoga
ham yaha ampere’ law laga rhe hai usme u_0 x i(enclosed) hota hai isme i_enclosed me to utna hi current lenge na jitna 4cm radius ke area se pass hoga
Jab jake hame magnetic field milega 4cm pr kitna hai
ooooohhhhhh hn okk
Agar hamne 2pi le lia fir to complete magnetic field ajyega
to agar mujhe to 4 cm wale area ka nikalna hai to i have to get per unit kitna hai and then 4 cm me kitna hai and then maxwell eqn
Exactly
yppp smjh gya
unne J ka use kia par yaha current uniform hai aap unitary method se bhi kr skte the
But j wala method is more correct cause kisi question me current uniform na dia ho
hnn vo to hai
+solved @SirLancelotDuLac @Real potato
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