11 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.I know how to solve that but i don’t understand it properly nd unable to visualise
@hardcoreisdead can you try dis
thermal physics toh bilkul revised nahi hai
basically to understand it first conisder a simpler case where only the measuring stale of steel ( red ) can expansd, lenght of copper rod ( blue ) is l0 now we are basically looking for a point of steel rodl that will after heating exactly be equal to the lenght of copper as the scale elonagtes, we call tht point l and after elongation its lenght is l0 so here ive found l ( * the length that scale measures after heating* )
as u can also see l is less than l0 which means scale will acctually measure less lenght as it itself is elongated
Tysm ill check it out soon
yea and then for this que basically the green mark should reach the new lenght of stel afetr heatign and sicne steel can also expand this time, the new lenght of steel will be js l0(1+alphaS(T)) where l0 is initial lenght of steel, and the green mark should be fo this lenght after heating an du cn get lenght of it using firt case which i told
but the length of the point that we took in steel scale and length of copper rod is equal? How do we know that
No we are assuming a random lenght and we made it equal using equations, after expansion of both rods we jist assumed a random point b4, and after expansion that rabfom point should be on tip of blue scale as thats what the red one would measure right?
@Real potato ok here?