29 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.is alpha 6
without mass of charge particle u cant comment on com
if u ignore it then ofc its the geometric centre
of the entire sphere
Yes alpha is 6
Kese kara
Nahi mei kehra, jo half hemispheres ha unke centre of masses ka distance
@CorrodedCoffin
F = A * pressure
11th mein derive nahi kara tha
?
ring element leke
Vo to hemisphere ka tha na
oh half hemisphere
mb
Electrostatic pressure se
yeh hemispherical sphere kya hai
Dekh ek sphere ha
Usko kata
meine toh 2 hemispheres maanke kara
Jo hemisphere bana usko kaata
Ab ye kaatke jo 2 quarter se bane ha, unki charge density ha sigma 1 and 2
..
pi r ^2 sigma 1 sigma 2 / 2 epsilon
ques ki lang ajeeb si hai
Ye kara tha mene, usse 12 aaraha tha com vale method seðŸ˜
Ruk bhejta hu
we can assume total charge on com always ?
ig so
@integralofe^2v
Idts u can write the entire charges on sphere as a single point charge, as the electric field due to both of these isnt same in center, instead try finding the electric field due to 1 hemisphere at center and multiply by charge to find force
is pi r ^2 sigma 1 sigma 2 / 2 epsilon
pir^2 is projected area and the other term is electrostatic pressure
yea that works too
alrr
Electric field due to half hemisphere at the centre?
yes
sigma/4epsilon
u an derive byt aking ring elements
Hemisphere and half hemisphere ki same hoti kya
no wait mb i meant field due to full hemisphere ( half sphere) we dont need half hemisphere here, its sigma/4spsilon for this shape
@integralofe^2v can u please send a solution to this.
Thanks a lot
+solved @integralofe^2v
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