Electrochemistry calculation of n
Toh agar koi Rittick Sir ke classes kiye hue hain toh please ye dekhiye
-- Ec ke L4 mein (Yakeen 4.0 25) sir ne bola tha calculation of n, n = st. coeff x f,, par what about the cases? is it the same as calculation of f in redox rxn jo sir ne karaya tha? like for eg - Is it true for disproportionation also? I mean, in redox rxn, rittick sir said that, f = valency factor = |fOfR/fO+fR|, so if n = st coefficient x f, then n = |nOnR/nO+nR|, but then in case-iii where if 1 atom gets oxidised and one is reduced like KClO3-> KCl+3/2 O2, There, ftotal= |f ox|= |f red| so n total = |n ox| = |n red| which is again the same, But the problem arises with, KSCN -> SO42- + KCN, Here, f total= |f ox - f red|,, but what about calculation of n ?? i said in chatgpt and it said, n total = |n ox + n red| = st. coeff of molecule | f ox + f red|??? huh then its not the same,,,
-- Ec ke L4 mein (Yakeen 4.0 25) sir ne bola tha calculation of n, n = st. coeff x f,, par what about the cases? is it the same as calculation of f in redox rxn jo sir ne karaya tha? like for eg - Is it true for disproportionation also? I mean, in redox rxn, rittick sir said that, f = valency factor = |fOfR/fO+fR|, so if n = st coefficient x f, then n = |nOnR/nO+nR|, but then in case-iii where if 1 atom gets oxidised and one is reduced like KClO3-> KCl+3/2 O2, There, ftotal= |f ox|= |f red| so n total = |n ox| = |n red| which is again the same, But the problem arises with, KSCN -> SO42- + KCN, Here, f total= |f ox - f red|,, but what about calculation of n ?? i said in chatgpt and it said, n total = |n ox + n red| = st. coeff of molecule | f ox + f red|??? huh then its not the same,,,
