14 Replies
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@Gyro Gearloose
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CorrodedCoffin
CorrodedCoffinOP2w ago
lets say h height of water has been filled we want the bottom most particle to appear at a depth of 21/2 cm 21/2 = 3/4 * h h=14cm
Monishrules
Monishrules2w ago
no the observer now thinks that wherever the bottom most particle is now the new depth so the height of water should be half of that
Monishrules
Monishrules2w ago
No description
CorrodedCoffin
CorrodedCoffinOP2w ago
real depth = h apparent depth = h/2 for observer in air
Monishrules
Monishrules2w ago
not nessecary its not the apparent depth that matters its the fact that the water is filled upto half of the apparent depth
CorrodedCoffin
CorrodedCoffinOP2w ago
@integralofe^2v can u explain what the ques is asking precisely
integralofe^2v
basically first assum water is filled till height x then when obsevrer looks from top of beaker, it will see the bottom of beaker at a new level so basically for him the beakers length is just 21-x+x/u and for it to appear half filled, 21-x=x/u
CorrodedCoffin
CorrodedCoffinOP2w ago
hmmm yeah makes sense now apparent depth should be equal to the remaining portion of beaker to create an illusion of half filled
integralofe^2v
yaa
CorrodedCoffin
CorrodedCoffinOP2w ago
got it ek aur dekhna +solved @integralofe^2v
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