inherit two interface that have same properties

Hhellounlimited hi all, i have two interfaces that have member with same name inside, and i inhe...

Y

Yawnder•9/30/22, 6:01 AM

Yes it is, but I think you fundamentally don't understand what an interface is.

Y

Yawnder•9/30/22, 6:02 AM

An interface is not an implementation. An interface is a contract that says "whomever implements that interface has to expose [this thing]".

Y

Yawnder•9/30/22, 6:03 AM

Now, in your example, you said "Anything that implements

IMemo

IMemo

IMemo

IMemo has to provide an id, and anything that implements

IStickyNote

IStickyNote

IStickyNote

IStickyNote has to provide an id".

Y

Yawnder•9/30/22, 6:03 AM

If anything implements both, as long as it exposes an id, it matches both contracts so you're fine.

YYawnder If anything implements both, as long as it exposes an id, it matches both contra...

H

hellounlimitedOP•9/30/22, 6:08 AM

so these two conditions below are incorrect, and it shouldnt work this way if i implement an interface, is that what you mean?

Anything that implements IMemo has to provide an id, and anything that implements IStickyNote has to provide an id
If anything implements both, as long as it exposes an id, it matches both contracts so you're fine.

Anything that implements IMemo has to provide an id, and anything that implements IStickyNote has to provide an id
If anything implements both, as long as it exposes an id, it matches both contracts so you're fine.

Anything that implements IMemo has to provide an id, and anything that implements IStickyNote has to provide an id
If anything implements both, as long as it exposes an id, it matches both contracts so you're fine.

Anything that implements IMemo has to provide an id, and anything that implements IStickyNote has to provide an id
If anything implements both, as long as it exposes an id, it matches both contracts so you're fine.

Hhellounlimited so these two conditions below are incorrect, and it shouldnt work this way if i ...

Y

Yawnder•9/30/22, 6:09 AM

No, what I wrote (and you quoted) is what it actually is.

YYawnder No, what I wrote (and you quoted) is what it actually is.

H

hellounlimitedOP•9/30/22, 6:11 AM

ohh so it's correct.. hmm.. but how do we resolve the ambiguity if we want to access a member but both interface have same name?

Y

Yawnder•9/30/22, 6:12 AM

Why would there be an ambiguity?

H

hellounlimitedOP•9/30/22, 6:13 AM

foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

}

foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

}

foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

}

foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

}

H

hellounlimitedOP•9/30/22, 6:13 AM

im not sure but this is the exception visual studio give..

Y

Yawnder•9/30/22, 6:14 AM

New example:
There is a bar. To enter the bar, you need to be 18y or more.
There is a convenient store. To buy beer there, you need to be 18y or more.

If you are 20y old, is there an ambiguity as to if you can enter the bar or buy beer?

Y

Yawnder•9/30/22, 6:14 AM

As long as you meet the criteria, you're good.

YYawnder As long as you meet the criteria, you're good.

H

hellounlimitedOP•9/30/22, 6:16 AM

hmm.. because i inherit from both interfaces

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
 //if i access id member here i will get ambiguity exception 
 foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

 }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
 //if i access id member here i will get ambiguity exception 
 foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

 }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
 //if i access id member here i will get ambiguity exception 
 foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

 }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
 //if i access id member here i will get ambiguity exception 
 foreach (T note in allNote){
  note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

 }
  }
}

and both IMemo and IStickyNote have "id" member

so when i try to access "id" there's this message from visual studio ->//ambiguity between IMemo.id and IStickyNote.id

M

MODiX•9/30/22, 6:16 AM

Yawnder#7904

REPL Result: Success

interface IA { int MyInt { get; set ; } }
interface IB { int MyInt { get; set ; } }
class C : IA, IB { public int MyInt { get; set ; } }

var c = new C();
c.MyInt = 3;
Console.WriteLine(c.MyInt);

interface IA { int MyInt { get; set ; } }
interface IB { int MyInt { get; set ; } }
class C : IA, IB { public int MyInt { get; set ; } }

var c = new C();
c.MyInt = 3;
Console.WriteLine(c.MyInt);

interface IA { int MyInt { get; set ; } }
interface IB { int MyInt { get; set ; } }
class C : IA, IB { public int MyInt { get; set ; } }

var c = new C();
c.MyInt = 3;
Console.WriteLine(c.MyInt);

interface IA { int MyInt { get; set ; } }
interface IB { int MyInt { get; set ; } }
class C : IA, IB { public int MyInt { get; set ; } }

var c = new C();
c.MyInt = 3;
Console.WriteLine(c.MyInt);

Console Output

Compile: 658.462ms | Execution: 58.445ms | React with ❌ to remove this embed.

Hhellounlimited hmm.. because i inherit from both interfaces ``` public class MyNote <T> where T...

Y

Yawnder•9/30/22, 6:17 AM

No, your problem is because what you wrote is non-sense an just not valid code.

Y

Yawnder•9/30/22, 6:17 AM

You can't have a foreach in a class, it needs to be in a method.

YYawnder No, your problem is because what you wrote is non-sense an just not valid code.

H

hellounlimitedOP•9/30/22, 6:18 AM

ok i edited the code, i was typing in discord so there was a mistake

H

hellounlimitedOP•9/30/22, 6:18 AM

but in the visual studio editor, the error is only in the ambiguity line

Y

Yawnder•9/30/22, 6:18 AM

Once again, it's invalid code...

H

hellounlimitedOP•9/30/22, 6:19 AM

mm.. why..?

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
   //if i access id member here i will get ambiguity exception 
   foreach (T note in allNote){
       note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

    }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
   //if i access id member here i will get ambiguity exception 
   foreach (T note in allNote){
       note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

    }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
   //if i access id member here i will get ambiguity exception 
   foreach (T note in allNote){
       note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

    }
  }
}

public class MyNote <T> where T :IMemo, IStickyNote {
 
  public void Test(){
   //if i access id member here i will get ambiguity exception 
   foreach (T note in allNote){
       note.id = 1234; //ambiguity between IMemo.id and IStickyNote.id

    }
  }
}

Y

Yawnder•9/30/22, 6:19 AM

Look, I've explained, then I've shown you with some code that compiled and executed, that it works, not sure what else I can do.

H

hellounlimitedOP•9/30/22, 6:19 AM

ohh i should create a new object?

Y

Yawnder•9/30/22, 6:19 AM

allNote

allNote

allNote

allNote doesn't exist. It can't work.

YYawnder `allNote` doesn't exist. It can't work.

H

hellounlimitedOP•9/30/22, 6:20 AM

ok supposed i have this valid allNote, bcs i get the allNote from database, so i didnt post it in the code....

T

Thinker•9/30/22, 6:20 AM

Never mind the question of why

MyNote

MyNote

MyNote

MyNote is generic in the first place

TThinker Never mind the question of why `MyNote` is generic in the first place

H

hellounlimitedOP•9/30/22, 6:21 AM

yah it's a code that i take over.. i think they've some requirement on this previously..

H

hellounlimitedOP•9/30/22, 6:22 AM

but actually the problem is only 1, the exception only gives me "ambiguity...." from visual studio

Y

Yawnder•9/30/22, 6:22 AM

It can't say that as any and all code you've shown doesn't compile.

Y

Yawnder•9/30/22, 6:23 AM

Anyways, I'm off to bed.

T

Thinker•9/30/22, 6:28 AM

You can't unify both interfaces with a single

IHasId

IHasId

IHasId

IHasId interface?

TThinker You can't unify both interfaces with a single `IHasId` interface?

H

hellounlimitedOP•9/30/22, 6:31 AM

hmm.. i saw that there'll be lots of changes.. there's solution to this from the error https://learn.microsoft.com/en-us/dotnet/csharp/language-reference/compiler-messages/cs0229?f1url=%3FappId%3Droslyn%26k%3Dk(CS0229) - i click from the suggested link from the error

H

hellounlimitedOP•9/30/22, 6:32 AM

but if i append ((IInterface)x).properties, it'll kind of messy..

T

Thinker•9/30/22, 6:35 AM

I think if you just have a single

IHasId

IHasId

IHasId

IHasId interface which both

IMemo

IMemo

IMemo

IMemo and

IStickyNote

IStickyNote

IStickyNote

IStickyNote inherits from, then it'll work much better.

H

hellounlimitedOP•9/30/22, 6:36 AM

i see.. alright.. i'll try to refactor the code..

TThinker I think if you just have a single `IHasId` interface which both `IMemo` and `ISt...

H

hellounlimitedOP•9/30/22, 6:36 AM

thanks!

inherit two interface that have same properties

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