Vapour Pressure
They assked for Vapour Pressure of Solution M , so it should be P0A Xa + P0B Xb right? in the soln they only did P0A Xa why? jee adv pyq none of the options match total vapour pressure
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator automobiles.
A solution M
is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixtrue is 0.9
Given Freezing point depression constant of water (kwater )=1.86 K kg mol−1
Freezing point depression constant of ethanol (kethanol f)=2.0Kkgmol−1
Boiling point elevation constant of water (kwater b)=0.52Kkgmol−1
Boiling point elevation constant of ethanol (kethanol b)=1.2Kkgmol−1
Standard freezing point of water =273 K
Standard freezing point of ethanol =155.7 K
Standard boiling point of water =373 K
Standard boiling point of ethanol =351.5 K
Vapour pressure of pure water =328 mm
of Hg
Vapour pressure of pure ethanol =40 mm
of Hg
Molecular weight of water =18 g mol−1
Molecular weight of ethanol =46 g mol−1
In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.Question:
The vapour pressure of the solution M
is
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator automobiles.
A solution M
is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixtrue is 0.9
Given Freezing point depression constant of water (kwater )=1.86 K kg mol−1
Freezing point depression constant of ethanol (kethanol f)=2.0Kkgmol−1
Boiling point elevation constant of water (kwater b)=0.52Kkgmol−1
Boiling point elevation constant of ethanol (kethanol b)=1.2Kkgmol−1
Standard freezing point of water =273 K
Standard freezing point of ethanol =155.7 K
Standard boiling point of water =373 K
Standard boiling point of ethanol =351.5 K
Vapour pressure of pure water =328 mm
of Hg
Vapour pressure of pure ethanol =40 mm
of Hg
Molecular weight of water =18 g mol−1
Molecular weight of ethanol =46 g mol−1
In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.Question:
The vapour pressure of the solution M
is
