Doubt regarding free fall of block in inclined plane...
"Find acceleration (a) of Inclined plane, so that Block (m mass) will free fall",, now wherever I see the answer, it's always "For free fall N = 0, so ma sin theta = mgcos theta"...
My doubt is that, to free fall a block, all you need is mg, right? So, why only N = 0, ma should be = 0 also.. even, N should cancel ma.. so that only mg remains.. but if we do N=0 its just Normal force being 0, the horizontal acceleration remains there.
I think N = mgcos theta should be answer.. but it isn't
My doubt is that, to free fall a block, all you need is mg, right? So, why only N = 0, ma should be = 0 also.. even, N should cancel ma.. so that only mg remains.. but if we do N=0 its just Normal force being 0, the horizontal acceleration remains there.
I think N = mgcos theta should be answer.. but it isn't
