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iTeachChem6mo ago
asdf

Resonance basics

How is this possible? As if the -ve charge goes on the benzene ring then one of the pi bonds will be adjacent to -ve charge, breaking conjugation. So how does this structure have five resonance structures?
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@Dexter
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Note for OP
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1 =Sin^2x + Cos^2x
@asdf
asdf
asdfOP6mo ago
Yes understood forgot that the pi bond can go out thanks
1 =Sin^2x + Cos^2x
👍
asdf
asdfOP6mo ago
+solved @Mast Raho Yar
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