iTeachChem•9mo ago

Gauss Law/ Electric potential

The answer according to me should be 2rhor/3epsilon along the d vector

rn_image_picker_lib_temp_6a9a6bf8-7893-4d21-8729-c994e7c91b7a.jpg

iTeachChem Helper•4/6/25, 5:58 AM

@Gyro Gearloose

iTeachChem Helper•4/6/25, 5:58 AM

Note for OP

+solved @user1 @user2...

+solved @user1 @user2...

to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

FusionOP•4/6/25, 5:59 AM

The answer I got isn't even in the options. The correct answer is option (3)

FFusion The answer I got isn't even in the options. The correct answer is option (3)

Opt•4/6/25, 8:00 AM

It is option 3.

Opt•4/6/25, 8:00 AM

You can split the field into each sphere's contribution and add.

Opt•4/6/25, 8:04 AM

Each sphere's contribution is nothing but the field due the all the charge enclosed in the sphere of radius (d/2), since any spherical shell elements do not impact the field.

We take d/2 because, by symmetry, field at the centre of the region is identical to that everywhere in the region (no charge density, so boundary conditions satisfy the whole space)

You get that the field due to each sphere is ρd/6ε in the d direction (unit vector), so, taking two contributions, we get ρd/3ε (d unit vector)

But, d(d unit vector) = d vector.

So that gives you option 3

FusionOP•4/6/25, 8:14 AM

I don't understand why we take d/2

FusionOP•4/6/25, 8:15 AM

Wdym by 'no charge density so boundary conditions satisfied' @Opt

FFusion Wdym by 'no charge density so boundary conditions satisfied' @Opt

Opt•4/6/25, 9:11 AM

Ok, long story short, because of the options, we can assume that field is uniform within the region, and therefore, we can just consider field at the centre

FusionOP•4/7/25, 10:51 AM

Alright

FusionOP•4/7/25, 10:51 AM

+closed @Opt

FusionOP•4/7/25, 10:51 AM

+help

iTeachChem Helper•4/7/25, 10:51 AM

Commands

+help+help- Shows this embed.
+solved @user1, @user2...+solved @user1, @user2...- Marks the post as solved and archives it. Only the OP of that post can use this command. Mention the users to give them the credit of solving your doubt.
+stats+stats- View your doubt and quiz stats. Mention the user with the command to view their stats.
+lb doubts+lb doubts- Leaderboard to keep track of the top doubt solvers.
+lb quiz+lb quiz- Leaderboard to keep track of the top users in quiz.
+check+check- Returns all active doubt posts in the last 24 hrs.
+unsolved+unsolved- Retruns all active doubt posts (7 days).
+threads+threads- Get info about your doubt posts. Mention the user with the command to view their posts.
+link+link- Link to the Google sheets.
+ping+ping- Pong!
+about+about

See Info about the Bot.

Opt•4/7/25, 10:51 AM

It's solved

FusionOP•4/7/25, 10:51 AM

+solved @Opt

iTeachChem Helper•4/7/25, 10:51 AM

Post locked and archived successfully!

Archived by

@895699982265511976 (895699982265511976)

Time

April 7, 2025

Solved by

@763645886500175892 (763645886500175892)

Gauss Law/ Electric potential

Similar Threads

Similar Threads

Similar Threads