18 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.1st ques mein path 1-2-3 mein hoga na heat given
so deltaU 2->3 + work done 2->3 + deltaU1->2
right?
elliptical is 2 - 3 - 4 right
and area under that curve will be the work done
you have T2 and T4 from PV = RT, so you have dU for 2-3-4
waha se you can get heat?
3->4 is heat loss tho
we need this area for workdone
Cool. So it’s geometry na from there.
Quarter circle and rectangle?
i have the work done figured out
change in internal energy is a bit bothersome
why?cant we just do 1/2 f R*deltaT
delta T can be written in terms of P and V
deltaT = 2PV-PV/2 right?
yeah getting the same
solve further
no option matches
is it c?
yepp
T at different points should work from PV = RT na
do it only for 2-3 since qn is asking for elliptical path
although work done dono ka same hai, change internal energy alag aaegi islie ig u were getting another answer
bruh ques padhna chahiye tha pura
thanx
+solved @vj25_
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