iTeachChem•6mo ago

amperes law

i am getting an ans but am not sure if it correct ( key nahi hai)

CorrodedCoffinOP•7/11/25, 8:50 AM

posting my soln

iteachchemhelperv2•7/11/25, 8:50 AM

@Gyro Gearloose

iteachchemhelperv2•7/11/25, 8:50 AM

Note for OP

+solved @user1 @user2...+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

CorrodedCoffinOP•7/11/25, 8:52 AM

CorrodedCoffinOP•7/11/25, 8:52 AM

,rotate

TeXit•7/11/25, 8:53 AM

CorrodedCoffinOP•7/11/25, 8:53 AM

CorrodedCoffinOP•7/11/25, 8:54 AM

AB means integral B.dl from A to B

CorrodedCoffinOP•7/12/25, 10:13 AM

@Opt @SirLancelotDuLac @Real potato help pls

CCorrodedCoffin Click to see attachment

SirLancelotDuLac•7/12/25, 10:22 AM

Yeah man, the answer seems correct.

SirLancelotDuLac•7/12/25, 10:22 AM

Half of all current is q.omega/4pi

SirLancelotDuLac•7/12/25, 10:22 AM

And considering an infinitely big square thingy, it works.

CorrodedCoffinOP•7/12/25, 10:24 AM

Nah it's wrong

CCorrodedCoffin Nah it's wrong

SirLancelotDuLac•7/12/25, 10:45 AM

Lol I have forgor physix lmao

CCorrodedCoffin i am getting an ans but am not sure if it correct ( key nahi hai)

Opt•7/12/25, 11:34 AM

Take magnetic moment and do the integral of magnetic dipole field.

Opt•7/12/25, 11:35 AM

Magnetic moment is just (q/2m)(angular momentum)

CorrodedCoffinOP•7/12/25, 11:59 AM

ok so first of all what i did is wrong

CorrodedCoffinOP•7/12/25, 12:00 PM

what i did here isnt symmetrical since the current in wires would distort the magnetic fields

OOpt Take magnetic moment and do the integral of magnetic dipole field.

CorrodedCoffinOP•7/12/25, 12:00 PM

yeh sab toh nahi padha abhi

CorrodedCoffinOP•7/12/25, 12:00 PM

can u tell using amperes law

Opt•7/12/25, 12:01 PM

Amperes law applies for a closed loop

CorrodedCoffinOP•7/12/25, 12:01 PM

yeah

CorrodedCoffinOP•7/12/25, 12:01 PM

we can close the loop

Opt•7/12/25, 12:01 PM

Opt•7/12/25, 12:02 PM

Just do the integration my good man

CorrodedCoffinOP•7/12/25, 12:02 PM

i dont understand your integration method tho

Opt•7/12/25, 12:02 PM

You got field expression na?

CorrodedCoffinOP•7/12/25, 12:04 PM

ik how to find magnetic field at centre of given system

CorrodedCoffinOP•7/12/25, 12:04 PM

nothing else

Opt•7/12/25, 12:04 PM

Electric dipole ka axial field formula patha hai na?

Opt•7/12/25, 12:05 PM

Replace 1/ε with μ,
Replace p with m, and that's magnetic field along axis of magnetic dipole

OOpt Electric dipole ka axial field formula patha hai na?

CorrodedCoffinOP•7/12/25, 12:40 PM

nhi padha abhi...

CCorrodedCoffin nhi padha abhi...

Opt•7/12/25, 12:44 PM

Electrostatics nahi kiya hai kya???

OOpt Take magnetic moment and do the integral of magnetic dipole field.

SirLancelotDuLac•7/12/25, 12:47 PM

Slight doubt: Don't we approximate the dipole formula strictly for large distances?

SSirLancelotDuLac Slight doubt: Don't we approximate the dipole formula strictly for large distanc...

Opt•7/12/25, 12:48 PM

True. That might be an issue.

Opt•7/12/25, 12:49 PM

We get zero if we follow my method I think. Lol.

OOpt We get zero if we follow my method I think. Lol.

SirLancelotDuLac•7/12/25, 12:51 PM

My thinking was ki take a half plane with the edge coinciding with z axis, take a big square with one of the sides as z-axis and making the square infinite, we just get the value as mu_0 times I

SirLancelotDuLac•7/12/25, 12:51 PM

Which would give mu_0 times q.omega/2pi

CCorrodedCoffin Nah it's wrong

SirLancelotDuLac•7/12/25, 12:51 PM

Oh right its 2pi not 4pi sorry