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A Study Community for Everyone and Everything. We have weekly sessions on Spirituality, Math and Science! JEE, NEET prep? All doubts are crowdsourced. Hare Krishna!
hello arent the left nitrogen lone pairs conjugated and the same with the right side upper nitrogen so i expected one of the pyridine type nitrogens to donate but its not,
Do we consider the hyperconjugation exerted by the methyl group (even though Hyperconjugation results in an increased stability of Carbocations. Alkenes and Radicals only) ? If so, the order of stability would be: 2 > 3 > 1. If not, the order of stability would be: 3 > 2 > 1
i dont think any of the options is right. the latter pic is what i feel the graph should be like. Is it right? like shouldnt it dip while discharging unlike opt 1 which is the correct ans. it wont drop to 0 so 3 is incorrect too