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iTeachChem
•
6mo ago
CorrodedCoffin
integration 3
integrate wrt x
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integration 3
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I
iTeachChem Helper
•
7/22/25, 6:14 AM
@Apu
I
iTeachChem Helper
•
7/22/25, 6:14 AM
Note for OP
+solved @user1 @user2...
+solved @user1 @user2...
to close the thread when your doubt is solved
. Mention the users who helped you solve the doubt
. This will be added to their stats
.
C
CorrodedCoffin
OP
•
7/22/25, 6:15 AM
pls explain your thought process
V
Varun_Arora
•
7/22/25, 6:18 AM
Yo
V
Varun_Arora
•
7/22/25, 6:18 AM
You tried partial fractions
V
Varun_Arora
•
7/22/25, 6:18 AM
?
V
Varun_Arora
You tried partial fractions
C
CorrodedCoffin
OP
•
7/22/25, 6:20 AM
not applicable
C
CorrodedCoffin
OP
•
7/22/25, 6:20 AM
these arent polynomials
V
Varun_Arora
•
7/22/25, 6:20 AM
Take expression
=
$
$
[
(Ax
)
/
(2x
^2
+ 3
)
]
+
[B
/x
-1
]
+
[C
/x
+1
]
$
$
T
TeXit
•
7/22/25, 6:20 AM
Enamine
V
Varun_Arora
•
7/22/25, 6:21 AM
Ohhh
V
Varun_Arora
•
7/22/25, 6:21 AM
That 1
/2
V
Varun_Arora
•
7/22/25, 6:21 AM
It wasn
't visible earlier
V
Varun_Arora
•
7/22/25, 6:21 AM
Sorry
C
CorrodedCoffin
OP
•
7/22/25, 6:21 AM
np np
V
Varun_Arora
•
7/22/25, 6:21 AM
Open it up
V
Varun_Arora
•
7/22/25, 6:21 AM
We could do some trig sub here I suppose
C
CorrodedCoffin
OP
•
7/22/25, 6:22 AM
i actually know what to do but i dont have a logic for it
C
CorrodedCoffin
OP
•
7/22/25, 6:22 AM
like
"why
" this
V
Varun_Arora
•
7/22/25, 6:23 AM
It
's a shorthand
V
Varun_Arora
•
7/22/25, 6:23 AM
You see
V
Varun_Arora
•
7/22/25, 6:23 AM
Squares under a square root
V
Varun_Arora
•
7/22/25, 6:23 AM
You think of trig identities
V
Varun_Arora
•
7/22/25, 6:23 AM
That gives you a hint as to convert into a useful form
V
Varun_Arora
•
7/22/25, 6:23 AM
There must be some other method too
V
Varun_Arora
•
7/22/25, 6:24 AM
But this is the most conventional
V
Varun_Arora
•
7/22/25, 6:24 AM
And frequently used
C
CorrodedCoffin
OP
•
7/22/25, 6:25 AM
x
=sectheta
?
?
C
CorrodedCoffin
x=sectheta ??
V
Varun_Arora
•
7/22/25, 6:26 AM
tan would work better no
?
V
Varun_Arora
tan would work better no?
C
CorrodedCoffin
OP
•
7/22/25, 6:27 AM
tan
^2
-1 would be harder to deal with
A
altf4
•
7/22/25, 6:27 AM
@hardcoreisdead
A
altf4
•
7/22/25, 6:27 AM
can u send ans
V
Varun_Arora
•
7/22/25, 6:27 AM
After converting it to x
^2
+ a
^2
C
CorrodedCoffin
tan^2-1 would be harder to deal with
V
Varun_Arora
•
7/22/25, 6:27 AM
Naah not it in that
A
altf4
•
7/22/25, 6:27 AM
im getting something i want to cnf whether its correct or not
V
Varun_Arora
•
7/22/25, 6:27 AM
First open it
A
altf4
can u send ans
C
CorrodedCoffin
OP
•
7/22/25, 6:27 AM
indefinite pakcage page 42
A
altf4
•
7/22/25, 6:27 AM
alr
V
Varun_Arora
•
7/22/25, 6:27 AM
Convert it to the x
^2
+ a
^2
C
CorrodedCoffin
OP
•
7/22/25, 6:28 AM
ok trying
C
CorrodedCoffin
indefinite pakcage page 42
V
Varun_Arora
•
7/22/25, 6:28 AM
Such a smooth convo lmao
V
Varun_Arora
Convert it to the x^2 + a^2
C
CorrodedCoffin
OP
•
7/22/25, 6:28 AM
ek sec ismein kaise aayega
C
CorrodedCoffin
OP
•
7/22/25, 6:28 AM
root
( degree 4
)
A
altf4
•
7/22/25, 6:28 AM
i converted the numerator to 1
/5
*
[
(2x
^2
+3
)
-2
(x
^2
-1
)
] then it was coming standard integrals for both iirc
C
CorrodedCoffin
root( degree 4 )
V
Varun_Arora
•
7/22/25, 6:29 AM
Further substitution
A
altf4
•
7/22/25, 6:29 AM
nah nvm
V
Varun_Arora
•
7/22/25, 6:29 AM
t2 ko x maan ke and stuff
V
Varun_Arora
•
7/22/25, 6:30 AM
Sorry
V
Varun_Arora
•
7/22/25, 6:30 AM
X square to t maan ke
V
Varun_Arora
•
7/22/25, 6:30 AM
Whatever
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