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iTeachChem
•
4mo ago
________
SnS
How should I split the general term
?
iTeachChem
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I
iTeachChem Helper
•
9/7/25, 10:54 AM
@Apu
I
iTeachChem Helper
•
9/7/25, 10:54 AM
Note for OP
+solved @user1 @user2...
+solved @user1 @user2...
to close the thread when your doubt is solved
. Mention the users who helped you solve the doubt
. This will be added to their stats
.
I
iTeachChem
•
9/7/25, 10:57 AM
denominator
:
(n
)
(n
+1
)
(n
+2
)
(2
)
^
(n
+1
)
_
________
OP
•
9/7/25, 10:58 AM
yup
_
________
OP
•
9/7/25, 10:58 AM
numerator is
_
________
OP
•
9/7/25, 10:58 AM
r
^2
+6r
+ 12
I
iTeachChem
•
9/7/25, 10:58 AM
something
+1
I
iTeachChem
•
9/7/25, 10:58 AM
Ah
I
iTeachChem
•
9/7/25, 10:58 AM
bro
I
iTeachChem
•
9/7/25, 10:58 AM
thats messed up
_
________
OP
•
9/7/25, 10:59 AM
its quad
I
iTeachChem
thats messed up
_
________
OP
•
9/7/25, 10:59 AM
lowkey
_
________
r^2 +6r + 12
I
iTeachChem
•
9/7/25, 11:00 AM
this doesnt track
I
iTeachChem
•
9/7/25, 11:00 AM
wait
_
________
OP
•
9/7/25, 11:00 AM
it doesn
't
_
________
OP
•
9/7/25, 11:00 AM
?
_
________
OP
•
9/7/25, 11:01 AM
$
$T
_r
=
\frac
{r
^2
+6r
+ 12
}
{r
(r
+1
)
(r
+2
) 2
^
{r
+1
}
}
$
$
_
________
OP
•
9/7/25, 11:01 AM
wait that
I
iTeachChem
•
9/7/25, 11:02 AM
the differences are 9
, 11
, 13
_
________
OP
•
9/7/25, 11:02 AM
Why is the LaTeX messed up
I
iTeachChem
the differences are 9, 11, 13
_
________
OP
•
9/7/25, 11:02 AM
thats AP with cd
= 2
_
________
OP
•
9/7/25, 11:02 AM
the general term should be correct
I
iTeachChem
•
9/7/25, 11:03 AM
got it
I
iTeachChem
•
9/7/25, 11:03 AM
sure so youve figured it out right
_
________
OP
•
9/7/25, 11:03 AM
hell naw
_
________
OP
•
9/7/25, 11:03 AM
the hard part is after that ig
_
________
OP
•
9/7/25, 11:05 AM
how do I split ts in the form of
+
-f
(r
+1
)
-
+ f
(r
)
T
TeXit
•
9/7/25, 11:05 AM
_
_
_
_
_
_
_
_
A
altf4
•
9/7/25, 11:42 AM
sum is till infinity right
@
_
_
?
A
altf4
sum is till infinity right @________ ?
_
________
OP
•
9/7/25, 12:16 PM
Yup
_
________
OP
•
9/8/25, 4:02 PM
gng
_
________
OP
•
9/8/25, 4:02 PM
anyone
?
C
CorrodedCoffin
•
9/8/25, 4:28 PM
@SirLancelotDuLac
T
TeXit
**\_\_\_\_\_\_\_\_**
M
Monishrules
•
9/9/25, 8:35 AM
have you tried vn
M
Monishrules
•
9/9/25, 8:35 AM
this looks vn able i guess
M
Monishrules
this looks vn able i guess
S
SirLancelotDuLac
•
9/9/25, 12:14 PM
Yeah but making vn is hard here
;
_
;
S
SirLancelotDuLac
•
9/9/25, 12:18 PM
S
SirLancelotDuLac
•
9/9/25, 12:18 PM
This would be the painstaking way
:
/
S
SirLancelotDuLac
•
9/9/25, 12:19 PM
G
.p
. sum till infinity ka integration is aln
(1
-r
) jiska integration is
-a
(1
-r
)
(ln
(1
-r
)
-1
)
S
SirLancelotDuLac
•
9/9/25, 12:20 PM
Jiska integration you can find by parts easily
.
S
SirLancelotDuLac
•
9/9/25, 12:20 PM
But still there ought to be a better method
S
SirLancelotDuLac
•
9/9/25, 12:21 PM
Actually you don
't have to find the third integral
S
SirLancelotDuLac
•
9/9/25, 12:21 PM
Just split the third term to 1
/r
(r
+1
) thingy and 1
/
(r
+1
)
(r
+2
) thingy
S
SirLancelotDuLac
•
9/9/25, 12:21 PM
It will be easier ig
.
_
________
OP
•
9/9/25, 2:55 PM
alright thanks
I
I
_
T
A
C
M
S
